Question

In Young's double slit experiment, the minimum amplitude is obtained when the phase difference of super-imposing waves is: (where n = 1, 2, 3, ...)

पर्याय

• zero

• (2n − 1)π

• nπ

• (n + 1)π

Answer 1

(2n − 1)π

Explanation:

For minima, phase diff. = odd integral multiple of π = (2n − 1)π.