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In Young's double slit experiment, the minimum amplitude is obtained when the phase difference of super-imposing waves is: (where n = 1, 2, 3, ...) -

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Question

In Young's double slit experiment, the minimum amplitude is obtained when the phase difference of super-imposing waves is: (where n = 1, 2, 3, ...)

Options

  • zero

  • (2n − 1)π

  • (n + 1)π

MCQ

Solution

(2n − 1)π

Explanation:

For minima, phase diff. = odd integral multiple of π = (2n − 1)π.

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