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Question
In Young's double slit experiment, the minimum amplitude is obtained when the phase difference of super-imposing waves is: (where n = 1, 2, 3, ...)
Options
zero
(2n − 1)π
nπ
(n + 1)π
MCQ
Solution
(2n − 1)π
Explanation:
For minima, phase diff. = odd integral multiple of π = (2n − 1)π.
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