मराठी

Income of 100 Students of Their Parents is Given as Follows - Mathematics

Advertisements
Advertisements

प्रश्न

Income of 100 students of their parents is given as follows:

Income
(in thousand Rs.)
No. of students
(f)
0 – 8 8
8 – 16 35
16 – 24 35
24 – 32 14
32 – 40 8

Draw an ogive for the given distribution on a graph sheet. Use a suitable scale for your exercise. Use your ogive to estimate:

  1. the median income.
  2. Calculate the income below which freeship will be awarded to students if their parents income is in the bottom 15%
  3. Mean income.

The incomes of the parents of 100 students in a class in a certain university are tabulated below.

Income
(in thousand ₹)
0 – 8 8 – 16 16 – 24 24 – 32 32 – 40
No. of students 8 35 35 14 8
  1. Draw a cumulative frequency curve to estimate the median income.
  2. If 15% of the students are given freeships on the basis of the income of their parents, find the annual income of parents, below which the freeships will be awarded.
  3. Calculate the Arithmetic mean.
आलेख

उत्तर

i. Cumulative frequency curve

Income
(in thousand Rs.)
No. of students
(f)
Cumulative
Frequency
Class Mark 
x
fx
0 – 8 8 8 4 32
8 – 16 35 43 12 420
16 – 24 35 78 20 700
24 – 32 14 92 28 392
32 – 40 8 100 36 288
  `sumf = 100`     `sumfx = 1832`

We plot the points (8, 8), (16, 43), (24, 78), (32, 92) and (40, 100) to get the curve as follows:


Here, N = 100

`=> N/2 = 50`

At y = 50, affix A.

Through A, draw a horizontal line meeting the curve at B.

Through B, a vertical line is drawn which meets OX at M.

OM = 17.6 units

Hence, median income = 17.6 thousands

ii. 15% of 100 student = `(15 xx 100)/100 = 15`

From c.f. 15, draw a horizontal line which intersects the curve at P.

From P, draw a perpendicular to x-axis meeting it at Q which is equal to 9.6.

Therefore, freeship will be awarded to students provided annual income of their parents is upto 9.6 thousands.

iii. Mean = `(sumfx)/(sumf) = 1832/100 = 18.32`

shaalaa.com
Finding the Median, upper quartile, lower quartile from the Ogive
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 24: Measure of Central Tendency(Mean, Median, Quartiles and Mode) - Exercise 24 (E) [पृष्ठ ३७५]

APPEARS IN

सेलिना Mathematics [English] Class 10 ICSE
पाठ 24 Measure of Central Tendency(Mean, Median, Quartiles and Mode)
Exercise 24 (E) | Q 5 | पृष्ठ ३७५

संबंधित प्रश्‍न

The marks obtained by 120 students in a test are given below:

Marks 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90 90-100
No. of
students
5 9 16 22 26 18 11 6 4 3

Draw an ogive for the given distribution on a graph sheet.

Use a suitable scale for ogive to estimate the following:
(1) The median.
(2) The number of students who obtained more than 75% marks in the test.
(3) The number of students who did not pass the test if minimum marks required to pass is 40


Marks obtained by 200 students in an examination are given below:

Marks  No. of students
0 – 10 5
10 – 20 11
20 – 30 10
30 – 40 20
40 – 50 28
50 – 60 37
60 – 70 40
70 – 80 29
80 – 90 14
90 – 100 6

Draw an ogive for the given distribution taking 2 cm = 10 marks on one axis and 2 cm = 20 students on the other axis. Using the graph, determine:

  1. The median marks.
  2. The number of students who failed if minimum marks required to pass is 40.
  3. If scoring 85 and more marks are considered as grade one, find the number of students who secured grade one in the examination.

  1. Use the information given in the adjoining histogram to construct a frequency table.
  2. Use this table to construct an ogive.

 


Class mark 12.5 17.5 22.5 27.5 32.5 37.5 42.5 
Frequency 12 17 22 27 30 21 16
  1. From the distribution, given above, construct a frequency table.
  2. Use the table obtained in part (a) to draw : (i) a histogram, (ii) an ogive.

The following table shows the distribution of the heights of a group of factory workers:

Ht. (cm): 150 – 155 155 – 160 160 – 165 165 – 170 170 – 175 175 – 180 180 – 185
No. of workers: 6 12 18 20 13 8
  1. Determine the cumulative frequencies.
  2. Draw the ‘less than’ cumulative frequency curve on graph paper. Use 2 cm = 5 cm height on one axis and 2 cm = 10 workers on the other.

Marks obtained by 200 students in an examination are given below:

Marks 0 - 10 10 - 20 20 - 30 30 - 40 40 - 50 50 - 60 60 - 70 70 - 80 80 - 90 90 - 100
Frequency 5 11 10 20 28 37 40 29 14 6

Draw an ogive for the given distribution taking 2 cm = 10 marks on one axis and 2 cm = 20 students on the other axis. Using the graph, determine:
(i) The median marks
(ii) The number of students who failed if minimum marks required to pass is 40.
(iii) If scoring 85 and more marks is considered as grade one, find the number of students who secured grade one in the examination.


Attempt this question on graph paper. Marks obtained by 200 students in examination are given below:

Marks 0 - 10 10 - 20 20 - 30 30 - 40 40 - 50 50 - 60 60 - 70 70 - 80 80 - 90 90 - 100
No. of students 5 10 14 21 25 34 36 27 16 12

Draw an ogive for the given distribution taking 2 cm = 10 makrs on one axis and 2 cm = 20 students on the other axis.
From the graph find:
(i) the median
(ii) the upper quartile
(iii) number of student scoring above 65 marks.
(iv) If to students qualify for merit scholarship, find the minimum marks required to qualify.


The mark of 200 students in a test were recorded as follows:

Marks % No. of students
10 - 19 7
20 - 29 11
30 - 39 20
40 - 49 46
50 - 59 57
60 - 69 37
70 - 79 15
80 - 89 7

Draw the cumulative frequency table.
Draw an ogive and use it to find:
(i) The median
(ii) The number of students who scored more than 35% marks.


Use graph paper for this question.
The table given below shows the monthly wages of some factory workers.
(i) Using the table, calculate the cumulative frequency of workers.
(ii) Draw the cumulative frequency curve.
Use 2 cm = ₹500, starting the origin at ₹6,500 on X-axis, and 2 cm = 100 worker at they Y-axis.
(iii) Use your graph to write down the median wages in ₹.

Wages in ₹
(CLass)
No. of workers (frequency) Cumulative frequency f(x)
6500 - 7000 10 -
7000 - 7500 18 -
7500 - 8000 22 -
8000 - 8500 25 -
8500 - 9000 17 -
9000 - 9500 10 -
9500 - 10000 8 -

The marks obtained by 120 students in a test are given below:

Marks 0 - 10 10 - 20 20 - 30 30 - 40 40 - 50 50 - 60 60 - 70 70 - 80 80 - 90 90 - 100
No. of Students 5 9 16 22 26 18 11 6 4 3

Draw an ogive for the given distribution on a graph sheet.
Use suitable scale for ogive to estimate the following :
(i) the median.
(ii) The number of students who obtained more than 75% marks in the test.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×