Advertisements
Advertisements
प्रश्न
Integrate the following with respect to x.
2 cos x – 3 sin x + 4 sec2x – 5 cosec2x
उत्तर
`int 2 cos x - 3 sinx + 4 sec^2x - 5 "cosec"^2x`
= `2 int cos x "d"x - 3 int sin x "d"x + 4 int sec^2x - 5 int "cosec"^2 x "d"x`
= 2 sin x + 3 cos x + 4 tan x + 5 cot x + c
APPEARS IN
संबंधित प्रश्न
Integrate the following with respect to x.
`(9x^2 - 4/x^2)^2`
Integrate the following with respect to x.
(3 + x)(2 – 5x)
Integrate the following with respect to x.
`sqrt(1 - sin 2x)`
Integrate the following with respect to x.
`(log x)^3/x`
Integrate the following with respect to x.
`(x^("e" - 1) + "e"^(x - 1))/(x^"e" + "e"^x)`
Integrate the following with respect to x.
`1/sqrt(9x^2 - 7)`
Integrate the following with respect to x.
`sqrt(x^2 - 2)`
Choose the correct alternative:
`int sqrt("e"^x) "d"x` is
Choose the correct alternative:
If `int_0^1 f(x) "d"x = 1, int_0^1 x f(x) "d"x = "a"`, and `int_0^1 x^2 f(x) "d"x = "a"^2`, then `int_0^1 ("a" - x)^2 f(x) "d"x` is
Choose the correct alternative:
`int_0^4 (sqrt(x) + 1/sqrt(x)) "d"x` is