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प्रश्न
Integrate the following with respect to x.
`("e"^x + 1)^2 "e"^x`
उत्तर
`int("e"^x + 1)^2 "e"^x "d"x int[("e"^x)^2 + 2"e"^x + 1]"e"^x "d"x`
= `int ("e"^(2x) * "e"^x+ 2"e"^x* "e"^x + "e"^x) "d"x`
= `int ("e"^(3x) + 2"e"^(2x) + "e"^x) "d"x`
= `"e"^(3x)/3 + (2"e"^(2x))/2 + "e"^x + "c"`
= `"e"^(3x)/3 + "e"^(2x) + "e"^x + "c"`
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