Advertisements
Advertisements
प्रश्न
Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging?
- from A to B and
- from A to C?
उत्तर
(a) From A to B.
Time for A to B = 2 min 30s
= 2 × 60 + 30
= 150 s
`"Average speed" = "total distance"/ "time interval"`
= `300/150`
= 2 ms-1
`"Average velocity" = "displacement"/ "time interval"`
= `300/150`
= 2 ms-1
(b) From A to C.
Time taken = A to B + B to C
= 150 + 60
= 210 s
Total distance = 300 + 100
= 400 m
∴ `"Average speed" = "total distace"/"time interval"`
= `400/210 `
= 1.9 m s-1
∴ `"Average velocity" = "displacement"/"time interval"`
= `200/210`
= 0.95 ms-1
APPEARS IN
संबंधित प्रश्न
During an experiment, a signal from a spaceship reached the ground station in five minutes. What was the distance of the spaceship from the ground station? The signal travels at the speed of light, that is, 3 × 108m s−1.
What is the SI unit of retardation ?
State whether speed is a scalar or a vector quantity. Give reason for your choice.
A motorcyclist starts from rest and reaches a speed of 6 m/s after travelling with uniform acceleration for 3 s. What is his acceleration ?
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
What is its average speed ?
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
How long does it take to travel 240 m ?
A bus moving along a straight line at 20 m/s undergoes an acceleration of 4 m/s2. After 2 seconds, its speed will be:
Express 15 m s-1 in km h-1.
Define variable velocity and give one example.
Write down the type of motion of a body along with the A – O – B of the following distance – time graph.
