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प्रश्न
Ksp of Ag2CrO4 is 1.1 × 10−12. what is the solubility of Ag2CrO4 in 0.1 M K2CrO4?
उत्तर
\[\ce{\underset{x}{Ag2CrO4} ⇌ \underset{2x}{2Ag^+} + \underset{x}{CrO^{2-}_4}}\]
x is the solubility of Ag2CrO4 in 0.1 M K2CrO4
\[\ce{\underset{0.1 M}{K2CrO4} ⇌ \underset{0.2 M}{2K^+} + \underset{0.1 M}{CrO^{2-}_4}}\]
[Ag+] = 2x
\[\ce{[CrO^{2-}_4]}\] = (x + 0.1) ≈ 0.1 ..........(∵ x << 0.1)
Ksp = \[\ce{[Ag^+]^2 [CrO^{2-}_4]}\]
1.1 × 10−12 = (2x)2 (0.1)
1.1 × 10−12 = 0.4x2
x2 = `(1.1 xx 10^-12)/0.4`
x = `sqrt((1.1 xx 10^-12)/0.4)`
x = `sqrt(2.75 xx 10^-12)`
x = 1.65 × 10−6 M
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