मराठी

Let a and b be two positive integers such that a = p3q4 and b = p2q3, where p and q are prime numbers. If HCF (a, b) = pmqn and LCM (a, b) = prqs, then (m + n)(r + s) = ______. - Mathematics

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प्रश्न

Let a and b be two positive integers such that a = p3q4 and b = p2q3, where p and q are prime numbers. If HCF (a, b) = pmqn and LCM (a, b) = prqs, then (m + n)(r + s) = ______.

पर्याय

  • 15

  • 30

  • 35

  • 72

MCQ
रिकाम्या जागा भरा

उत्तर

Let a and b be two positive integers such that a = p3q4 and b = p2q3, where p and q are prime numbers. If HCF (a, b) = pmqn and LCM (a, b) = prqs, then (m + n)(r + s) = 35.

Explanation:

Given two numbers

a = p3q4 and b = p2q3

p p3q4
p p2q4
p pq4
p q4
q q3
q q2
q q
  1

 

p p2q3
p pq3
q q3
q q2
q 1

Finding HCF

a = p3q4 = p × p × p × q × q × q × q

b = p2q3 = p × p × q × q × q

HCF = p × p × q × q × q

HCF = p2q3

Comparing HCF = p2q3 with HCF = pmqn

∴ m = 2, n = 3

p p3q4, p2q3 
p p2q4, p2q3
p pq4, q3
q q4, q3
q q3, q2
q q2, q
q q, 1
  1, 1

Finding LCM

LCM = p × p × p × q × q × q × q

LCM = p3q4

Comparing LCM = p3q4 with LCM = prqs

∴ r = 3, s = 4

Now, (m + n)(r + s) = (2 + 3) × (3 + 4)

= 5 × 7

= 35

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