Advertisements
Advertisements
प्रश्न
What is the smallest number that when divided by three numbers such as 35, 56 and 91 leaves remainder 7 in each case?
उत्तर
35 = 5 × 7
56 = 2 × 2 × 2 × 7
91 = 7 × 13
L.C.M. of 35, 56, 91 = 5 × 7 × 2 × 2 × 2 × 13 = 3640
∴ Required number = 3647 which leaves remainder 7 in each case.
APPEARS IN
संबंधित प्रश्न
The HCF of two numbers is 145 and their LCM is 2175. If one number is 725, find the other.
Write down the decimal expansions of the following rational numbers by writing their denominators in the form 2m × 5n, where, m, n are non-negative integers.\[\frac{129}{2^2 \times 5^7}\]
If the prime factorization of a natural number n is 23 ✕ 32 ✕ 52 ✕ 7, write the number of consecutive zeros in n.
For what value of natural number n, 4n can end with the digit 6?
Find the L.C.M. and H.C.F. of 408 and 170 by applying the fundamental theorem of Arithmetic
Find the greatest number consisting of 6 digits which is exactly divisible by 24, 15, 36?
Find the least number that is divisible by the first ten natural numbers
If two positive integers A and B can be expressed as A = xy3 and B = xiy2z; x, y being prime numbers, the LCM (A, B) is ______.
Show that 12n cannot end with the digit 0 or 5 for any natural number n.
If two positive integers a and b are written as a = x3y2 and b = xy3, where x, y are prime numbers, then the result obtained by dividing the product of the positive integers by the LCM (a, b) is ______.
