Advertisements
Advertisements
प्रश्न
Find the least number that is divisible by the first ten natural numbers
उत्तर
The least number that is divisible by the first ten natural numbers is 2520.
Hint:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10
The least multiple of 2 & 4 is 8
The least multiple of 3 is 9
The least multiple of 7 is 7
The least multiple of 5 is 5
∴ 5 × 7 × 9 × 8 = 2520.
L.C.M is 8 × 9 × 7 × 5
= 40 × 63
= 2520
APPEARS IN
संबंधित प्रश्न
Find HCF and LCM of 404 and 96 and verify that HCF × LCM = Product of the two given numbers.
Express the number as a product of its prime factor:
156
Find the L.C.M. and H.C.F. of 408 and 170 by applying the fundamental theorem of Arithmetic
According to the fundamental theorem of arithmetic, if T (a prime number) divides b2, b > 0, then ______.
If LCM(x, 18) = 36 and HCF(x, 18) = 2, then x is ______.
Show that 12n cannot end with the digit 0 or 5 for any natural number n.
Let a and b be two positive integers such that a = p3q4 and b = p2q3, where p and q are prime numbers. If HCF (a, b) = pmqn and LCM (a, b) = prqs, then (m + n)(r + s) = ______.
The prime factorisation of the number 5488 is ______.
If two positive integers a and b are written as a = x3y2 and b = xy3, where x, y are prime numbers, then the result obtained by dividing the product of the positive integers by the LCM (a, b) is ______.
Three bells toll at intervals of 9, 12 and 15 minutes respectively. If they start tolling together, after what time will they next toll together?
