Question

मान ज्ञात कीजिए।

`4/5` tan² 60° + 3 sin² 60°

Answer 1

`4/5` tan² 60° + 3 sin² 60°

= `4/5 xx (sqrt 3)^2 +3 xx ( sqrt 3/2)^2`

= `4/5 xx 3 + 3 xx 3/4`

=`12/5 + 9/4`

= `[48 + 45 ]/20`

= `93/20`