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Question
मान ज्ञात कीजिए।
`4/5` tan2 60° + 3 sin2 60°
Sum
Solution
`4/5` tan2 60° + 3 sin2 60°
= `4/5 xx (sqrt 3)^2 +3 xx ( sqrt 3/2)^2`
= `4/5 xx 3 + 3 xx 3/4`
=`12/5 + 9/4`
= `[48 + 45 ]/20`
= `93/20`
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त्रिकोणमिति तालिका
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Chapter 8: त्रिकोणमिति - प्रश्नसंग्रह 8.2 [Page 112]
