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प्रश्न
Multiply the following:
3x2y2z2, 17xyz
बेरीज
उत्तर
We have,
3x2y2z2 and 17xyz
∴ 3x2y2z2 × 17xyz = (3 × 17)x2y2z2 × xyz
= 51x3y3z3
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३०]
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संबंधित प्रश्न
Find the product of the following pair of monomial.
4p, 0
Complete the table of products.
|
First monomial→ |
2x |
–5y |
3x2 |
–4xy |
7x2y |
–9x2y2 |
|
Second monomial ↓ |
||||||
| 2x | 4x2 | ... | ... | ... | ... | ... |
| –5y | ... | ... | –15x2y | ... | ... | ... |
| 3x2 | ... | ... | ... | ... | ... | ... |
| – 4xy | ... | ... | ... | ... | ... | ... |
| 7x2y | ... | ... | ... | ... | ... | ... |
| –9x2y2 | ... | ... | ... | ... | ... | ... |
Obtain the volume of a rectangular box with the following length, breadth, and height, respectively.
a, 2b, 3c
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| Length | breadth | height | |
| (i) | 2ax | 3by | 5cz |
| (ii) | m2n | n2p | p2m |
| (iii) | 2q | 4q2 | 8q3 |
Multiply (4x2 + 9) and (3x – 2)
Multiply the following:
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