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Obtain the differential equation by eliminating arbitrary constants from the following equations. y = Ae3x + B.e−3x - Mathematics and Statistics

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प्रश्न

Obtain the differential equation by eliminating arbitrary constants from the following equations.

y = Ae3x + Be−3x

बेरीज

उत्तर

y = Ae3x + B.e−3x ......(i)

Differentiating w.r.t. x, we get

`dy/dx = 3Ae^(3x) - 3 Be ^(-3x)`

Again, differentiating w.r. t. x, we get

`(d^2y)/dx^2 = 3A d/dxe^(3x) -3Bd/dx(e^(-3x))`

= `3A(3e^(3x)) - 3b(-3e^(-3x))`

=`9Ae^(3x)+9Be^(-3x)`

=`9(Ae^(3x)+Be^(-3x)) = 9y` ......[From(i)]

∴ `(d^2y)/dx^2 = 9y`

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Formation of Differential Equation by Eliminating Arbitary Constant
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Differential Equation and Applications - Exercise 8.2 [पृष्ठ १६३]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] 12 Standard HSC Maharashtra State Board
पाठ 8 Differential Equation and Applications
Exercise 8.2 | Q 1.1 | पृष्ठ १६३
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