मराठी

One half of a convex lens of focal length 10 cm is covered with a black paper. Can such a lens produce an image of a complete object placed at a distance of 30 cm from the lens? Draw a ray diagram to justify your answer. A 4 cm tall object is placed perpendicular to its principal axis of a convex lens of focal length 20 cm. - Science

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प्रश्न

One half of a convex lens of focal length 10 cm is covered with a black paper. Can such a lens produce an image of a complete object placed at a distance of 30 cm from the lens? Draw a ray diagram to justify your answer. A 4 cm tall object is placed perpendicular to its principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is 15 cm. Find the nature, position and the size of the image.

उत्तर

An image is formed from a number of rays from the object getting refracted by the lens. The complete image will be formed even if one half of the lens is covered. However, the brightness of the image will be less.

Case I: When the upper half of the lens is covered

In this case, rays of light coming from the object get refracted by the lower half of the lens. These rays meet at the other side of the lens to form the image of the given object as shown in the following figure:

Case II: When the lower half of the lens is covered

A convex lens can produce the complete image of the object even though half of the lens is covered. This is because light coming from the object can be refracted from the other half of the lens. However, the intensity of light will be reduced.

Given:-

Height of the object = h = 4 cm

Focal length of the convex lens = f = 20 cm

Object distance = u = −15 cm

Using the lens formula, we get

`1/`

`therefore1/`

`therefore`

Hence, the image is formed 60 cm in front of the lens on the same side as the object. Because v is negative, we can say that the image is virtual.

From the magnification formula for the lens, we get

`m=(h')/h=`

`thereforeh'=(`

Hence, the size of the image is h′ = 16 cm.

Because the height of the image is positive and greater than the height of the object, the image is erect and magnified.

So, we can conclude that the image is virtual, erect and magnified.

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