मराठी

Out of the Following Pairs of Compounds, the Unsaturated Compounds Are: (A) C2h6 and C4h6 (B) C6h12 and C5h12 (C) C4h6 and C6h12 (D) C2h6 and C4h10 - Science

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प्रश्न

Out of the following pairs of compounds, the unsaturated compounds are:
(a) C2H6 and C4H6
(b) C6H12 and C5H12
(c) C4H6 and C6H12
(d) C2H6 and C4H10

उत्तर

C4H6 and C6H12
C4H6 and C6H12 are unsaturated compounds as they correspond to the formula CnH2n-2 and CnH2n. They belong to the group alkyne and alkene respectively.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Carbon And Its Compounds - Exercise 1 [पृष्ठ २२३]

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लखमीर सिंह Chemistry (Science) [English] Class 10
पाठ 4 Carbon And Its Compounds
Exercise 1 | Q 41 | पृष्ठ २२३

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संबंधित प्रश्‍न

Explain in brief two main reasons for carbon forming a large number of compounds.


What will be the formula and electron dot structure of cyclopentane?


Draw the electron dot structures for ethanoic acid.


Write the electron-dot structures for ethyne.


What are hydrocarbons? Write the general formula of (i) saturated hydrocarbons, and (ii) unsaturated hydrocarbons and draw the structure of one hydrocarbon of each type. How can an unsaturated hydrocarbon be made saturated?

Which among the following are unsaturated hydrocarbons?

  1. \[\ce{H3C - CH2 - CH2 - CH3}\]
  2. \[\ce{H3C - C ≡ C - CH3}\]
  3. \[\begin{array}{cc}
    \ce{H3C - CH - CH3}\\
    |\phantom{..}\\
    \ce{CH3}\\
    \end{array}\]
  4. \[\begin{array}{cc}
    \ce{H3C - C = CH2}\\
    |\\
    \phantom{...}\ce{CH3}\\
    \end{array}\]

The name of the compound CH3 — CH2 — CHO is


Name the functional groups present in the following compounds

  1. CH3 CO CH2 CH2 CH2 CH3
  2. CH3 CH2 CH2 COOH
  3. CH3 CH2 CH2 CH2 CHO
  4. CH3 CH2 OH

  1. What are hydrocarbons? Give examples.
  2. Give the structural differences between saturated and unsaturated hydrocarbons with two examples each.
  3.  What is a functional group? Give examples of four different functional groups.

The formulae of four organic compounds are shown below. Choose the correct option

A B C D
\[\begin{array}{cc}
\phantom{.}\ce{H}\phantom{......}\ce{H}\\
\phantom{.}\backslash\phantom{.....}/\\
\ce{C = C}\\
/\phantom{.....}\backslash\\
\ce{H}\phantom{......}\ce{H}
\end{array}\]
\[\begin{array}{cc}
\phantom{........}\ce{H}\phantom{.....}\ce{O}\\
\phantom{.......}|\phantom{....}//\\
\ce{H - C - C}\\
\phantom{......}|\phantom{.....}\backslash\\
\phantom{...........}\ce{H}\phantom{.....}\ce{O - H}
\end{array}\]

\[\begin{array}{cc}
\ce{H}\phantom{....}\ce{H}\\
|\phantom{.....}|\\
\ce{H - C - C - H}\\
|\phantom{.....}|\\
\ce{H}\phantom{....}\ce{H}
\end{array}\]

 

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{....}\\
|\phantom{....}|\phantom{....}\\
\ce{H - C - C - O - H}\\
|\phantom{....}|\phantom{.....}\\
\ce{H}\phantom{....}\ce{H}\phantom{.....}
\end{array}\]

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