मराठी

Q 10.2 -

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प्रश्न

Q 10.2

बेरीज

उत्तर

Required sum = 0.8 + 0.88 + 0.888 +..........upto n terms
= 8(0.1 + 0.11 + 0.111 +..........upto n terms

=`8/9`(0.9 + 0.99 + 0.999 +..........upto n terms

=`8/9`[(1 - 0.1) + (1 - 0.01) +(1 -  0.001) +..........upto n terms]

=`8/9`[(1 + 1 + 1 +..........upto n terms) - ( 0.1 + 0.01 + 0.001 +..........upto n terms)]

=`8/9[(1 + 1 + 1 +.........."upto n terms") - (1/10 + 1/100 + 1/1000 +.........."upto n terms")]`

`=8/9[n-(1/10(1-1/10^n))/(1-1/10)]`   `[becauser = 1/10<1]`

`=8/9[n-10/9xx1/10(1-1/10^n)]`

`=8/9[n-1/9(1-1/10^n)]`

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Geometric Progression - Finding Sum of Their First ‘N’ Terms
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