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Question
Q 10.2
Sum
Solution
Required sum = 0.8 + 0.88 + 0.888 +..........upto n terms
= 8(0.1 + 0.11 + 0.111 +..........upto n terms
=`8/9`(0.9 + 0.99 + 0.999 +..........upto n terms
=`8/9`[(1 - 0.1) + (1 - 0.01) +(1 - 0.001) +..........upto n terms]
=`8/9`[(1 + 1 + 1 +..........upto n terms) - ( 0.1 + 0.01 + 0.001 +..........upto n terms)]
=`8/9[(1 + 1 + 1 +.........."upto n terms") - (1/10 + 1/100 + 1/1000 +.........."upto n terms")]`
`=8/9[n-(1/10(1-1/10^n))/(1-1/10)]` `[becauser = 1/10<1]`
`=8/9[n-10/9xx1/10(1-1/10^n)]`
`=8/9[n-1/9(1-1/10^n)]`
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Geometric Progression - Finding Sum of Their First ‘N’ Terms
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