Advertisements
Advertisements
प्रश्न
Read the statement below carefully and state, with reason, if it is true or false:
The acceleration vector of a particle in uniform circular motion averaged over one cycle is a null vector.
पर्याय
True
False
उत्तर
This statement is True.
Explanation:
In uniform circular motion (UCM), the direction of the acceleration vector points towards the centre of the circle. However, it constantly changes with time. The average of these vectors over one cycle is a null vector.
APPEARS IN
संबंधित प्रश्न
Why is the motion of a body moving with a constant speed around a circular path said to be accelerated?
Is it possible to have an accelerated motion with a constant speed? Explain.
Answer the following question.
Show that the centripetal force on a particle undergoing uniform circular motion is -mrω2.
Solve the following problem.
A car moves in a circle at a constant speed of 50 m/s and completes one revolution in 40 s. Determine the magnitude of the acceleration of the car.
Which one of the following is most likely not a case of uniform circular motion?
Which of the following graph represents uniform motion of a moving particle?
A string of length 'l' fixed at one end carries a mass 'm' at the other end. The string makes `3/pi` revolutions/second around the vertical axis through the fixed end as shown in figure. The tension 'T' in the string is ______.
The motion of the bus is ______ motion.
Earth also moves in circular orbit around sun once every year with on orbital radius of 1.5 × 1011 m. What is the acceleration of earth (or any object on the surface of the earth) towards the centre of the sun? How does this acceleration compare with g = 9.8 m/s2?
A small bead of mass m can move on a smooth circular wire (radius R) under the action of a force F = `"Km"/"r"^2` directed (r = position of bead r from P and K = constant) towards a point P within the circle at a distance R/2 from the centre. The minimum velocity should be ______ m/s of bead at the point of the wire nearest the centre of force (P) so that bead will complete the circle. (Take `"k"/(3"R")` = 8 unit)
