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प्रश्न
Reena is 6 years older than her brother Ajay. If the sum of their ages is 28 years, what are their present ages?
उत्तर
Let the present age of Ajay be x years.
Since Reena is 6 years older than Ajay, the present age of Reena will be (x + 6) years.
According to the question:
x + (x + 6) = 28
or, 2x + 6 = 28
or, 2x + 6 − 6 = 28 − 6 [Subtracting 6 from both the sides]
or, 2x = 22
or, `(2x)/2=22/2` [Dividing both the sides by 2]
or, x = 11
∴ Present age of Ajay = 11 years
Present age of Reena = x + 6 = 11 + 6
= 17 years
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संबंधित प्रश्न
Observe the patterns of digits made from line segments of equal length. You will find such segmented digits on the display of electronic watches or calculators.
If the number of digits formed is taken to be n, the number of segments required to form n digits is given by the algebraic expression appearing on the right of each pattern.
How many segments are required to form 5, 10, 100 digits of the kind −
Use the given algebraic expression to complete the table of number patterns.
S. No |
Expression |
Terms | |||||||||
1st | 2nd | 3rd | 4th | 5th | ... | 10th | ... | 100th | ... | ||
1 | 2n - 1 | 1 | 3 | 5 | 7 | 9 | - | 19 | - | - | - |
2 | 3n + 2 | 5 | 8 | 11 | 14 | - | - | - | - | - | - |
3 | 4n + 1 | 5 | 9 | 13 | 17 | - | - | - | - | - | - |
4 | 7n + 20 | 27 | 34 | 41 | 48 | - | - | - | - | - | - |
5 | n2 + 1 | 2 | 5 | 10 | 17 | - | - | - | - | 10001 | - |
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