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Question
Reena is 6 years older than her brother Ajay. If the sum of their ages is 28 years, what are their present ages?
Solution
Let the present age of Ajay be x years.
Since Reena is 6 years older than Ajay, the present age of Reena will be (x + 6) years.
According to the question:
x + (x + 6) = 28
or, 2x + 6 = 28
or, 2x + 6 − 6 = 28 − 6 [Subtracting 6 from both the sides]
or, 2x = 22
or, `(2x)/2=22/2` [Dividing both the sides by 2]
or, x = 11
∴ Present age of Ajay = 11 years
Present age of Reena = x + 6 = 11 + 6
= 17 years
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