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प्रश्न
RMS value of an alternating current flowing in a circuit is 5A. Calculate its peak value.
उत्तर
Peak value of ac, `I_0= I_(rms) xx sqrt(2) = 5sqrt(2) A`
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संबंधित प्रश्न
A device X is connected across an ac source of voltage V = V0 sin ωt. The current through X is given as
`I = I_0 sin (omega t + pi/2 )`
1) Identify the device X and write the expression for its reactance.
2) Draw graphs showing the variation of voltage and current with time over one cycle of ac, for X.
3) How does the reactance of the device X vary with the frequency of the ac? Show this variation graphically.
4) Draw the phasor diagram for the device X.
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