Advertisements
Advertisements
प्रश्न
Show That C0 + C1 + C2 + .... C9 = 512
उत्तर
Since C0 + C1 + C2 + C3 + …… + Cn = 2n
Putting n = 9, we get
C0 + C1 + C2 + …… + C9 = 29
∴ C0 + C1 + C2 + …… + C9 = 512
APPEARS IN
संबंधित प्रश्न
In the following expansion, find the indicated coefficient.
x3 in `(x^2 + (3sqrt(2))/x)^9`
In the following expansion, find the indicated coefficient.
x8 in `(2x^5 - 5/x^3)^8`
In the following expansion, find the indicated coefficient.
x9 in `(1/x + x^2)^18`
In the following expansion, find the indicated coefficient.
x–3 in `(x - 1/(2x))^5`
In the following expansion, find the indicated coefficient.
x–20 in `(x^3 - 1/(2x^2))^15`
Show That C0 + C1 + C2 + .... C8 = 256
Show That C1 + C2 + C3 + .... C7 = 127
Show That C1 + C2 + C3 + .... C6 = 63
Show That C0 + C2 + C4 + C6 + C8 = C1 + C3 + C5 + C7 = 128
Select the correct answer from the given alternatives.
The value 14C1 + 14C3 + 14C5 + ..... + 14C11 is
Select the correct answer from the given alternatives.
The value 11C2 + 11C4 + 11C6 + 11C8 is equal to
Expand (3x2 + 2y)5
Answer the following:
If the coefficient of x16 in the expansion of (x2 + ax)10 is 3360, find a
