Advertisements
Online Mock Tests
Chapters
2: Sequences and Series
3: Permutations and Combination
▶ 4: Methods of Induction and Binomial Theorem
5: Sets and Relations
6: Functions
7: Limits
8: Continuity
9: Differentiation
![Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 4 - Methods of Induction and Binomial Theorem Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 4 - Methods of Induction and Binomial Theorem - Shaalaa.com](/images/mathematics-and-statistics-2-arts-and-science-english-11-standard-maharashtra-state-board_6:eaa36ca82be449018bee0683dd2bba6f.jpg)
Advertisements
Solutions for Chapter 4: Methods of Induction and Binomial Theorem
Below listed, you can find solutions for Chapter 4 of Maharashtra State Board Balbharati for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board.
Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board 4 Methods of Induction and Binomial Theorem Exercise 4.1 [Pages 73 - 74]
Prove by method of induction, for all n ∈ N:
2 + 4 + 6 + ..... + 2n = n (n+1)
Prove by method of induction, for all n ∈ N:
3 + 7 + 11 + ..... + to n terms = n(2n+1)
Prove by method of induction, for all n ∈ N:
12 + 22 + 32 + .... + n2 = `("n"("n" + 1)(2"n" + 1))/6`
Prove by method of induction, for all n ∈ N:
12 + 32 + 52 + .... + (2n − 1)2 = `"n"/3 (2"n" − 1)(2"n" + 1)`
Prove by method of induction, for all n ∈ N:
13 + 33 + 53 + .... to n terms = n2(2n2 − 1)
Prove by method of induction, for all n ∈ N:
1.2 + 2.3 + 3.4 + ..... + n(n + 1) = `"n"/3 ("n" + 1)("n" + 2)`
Prove by method of induction, for all n ∈ N:
1.3 + 3.5 + 5.7 + ..... to n terms = `"n"/3(4"n"^2 + 6"n" - 1)`
Prove by method of induction, for all n ∈ N:
`1/(1.3) + 1/(3.5) + 1/(5.7) + ... + 1/((2"n" - 1)(2"n" + 1)) = "n"/(2"n" + 1)`
Prove by method of induction, for all n ∈ N:
`1/(3.5) + 1/(5.7) + 1/(7.9) + ...` to n terms = `"n"/(3(2"n" + 3))`
Prove by method of induction, for all n ∈ N:
(23n − 1) is divisible by 7
Prove by method of induction, for all n ∈ N:
(24n−1) is divisible by 15
Prove by method of induction, for all n ∈ N:
3n − 2n − 1 is divisible by 4
Prove by method of induction, for all n ∈ N:
5 + 52 + 53 + .... + 5n = `5/4(5^"n" - 1)`
Prove by method of induction, for all n ∈ N:
(cos θ + i sin θ)n = cos (nθ) + i sin (nθ)
Prove by method of induction, for all n ∈ N:
Given that tn+1 = 5tn + 4, t1 = 4, prove that tn = 5n − 1
Prove by method of induction, for all n ∈ N:
`[(1, 2),(0, 1)]^"n" = [(1, 2"n"),(0, 1)]` ∀ n ∈ N
Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board 4 Methods of Induction and Binomial Theorem Exercise 4.2 [Page 77]
Expand: `(sqrt(3) + sqrt(2))^4`
Expand: `(sqrt(5) - sqrt(2))^5`
Expand: (2x2 + 3)4
Expand: `(2x - 1/x)^6`
Find the value of `(sqrt(3) + 1)^4- (sqrt(3) - 1)^4`.
Find the value of `(2 + sqrt(5))^5 + (2 - sqrt(5))^5`
Prove that `(sqrt(3) + sqrt(2))^6 + (sqrt(3) - sqrt(2))^6` = 970
Prove that `(sqrt(5) + 1)^5 - (sqrt(5) - 1)^5` = 352
Using binomial theorem, find the value of (102)4
Using binomial theorem, find the value of (1.1)5
Using binomial theorem, find the value of (9.9)3
Using binomial theorem, find the value of (0.9)4
Without expanding, find the value of (x + 1)4 − 4(x + 1)3 (x − 1) + 6 (x + 1)2 (x − 1)2 − 4(x + 1) (x − 1)3 + (x − 1)4
Without expanding, find the value of (2x − 1)4 + 4(2x − 1)3 (3 − 2x) + 6(2x − 1)2 (3 − 2x)2 + 4(2x − 1)1 (3 − 2x)3 + (3 − 2x)4
Find the value of (1.02)6, correct upto four places of decimal
Find the value of (1.01)5, correct up to three places of decimals.
Find the value of (0.9)6, correct upto four places of decimal
Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board 4 Methods of Induction and Binomial Theorem Exercise 4.3 [Page 80]
In the following expansion, find the indicated term.
`(2x^2 + 3/(2x))^8`, 3rd term
In the following expansion, find the indicated term.
`(x^2 - 4/(x^3))^11`, 5th term
In the following expansion, find the indicated term.
`((4x)/5 - 5/(2x))^9`, 7th term
In the following expansion, find the indicated term.
`(1/3 + "a"^2)^12`, 9th term
In the following expansion, find the indicated term.
`(3"a" + 4/"a")^13`, 10th term
In the following expansion, find the indicated coefficient.
x3 in `(x^2 + (3sqrt(2))/x)^9`
In the following expansion, find the indicated coefficient.
x8 in `(2x^5 - 5/x^3)^8`
In the following expansion, find the indicated coefficient.
x9 in `(1/x + x^2)^18`
In the following expansion, find the indicated coefficient.
x–3 in `(x - 1/(2x))^5`
In the following expansion, find the indicated coefficient.
x–20 in `(x^3 - 1/(2x^2))^15`
Find the constant term (term independent of x) in the expansion of `(2x + 1/(3x^2))^9`
Find the constant term (term independent of x) in the expansion of `(x - 2/x^2)^15`
Find the constant term (term independent of x) in the expansion of `(sqrt(x) - 3/x^2)^10`
Find the constant term (term independent of x) in the expansion of `(x^2 - 1/x)^9`
Find the constant term (term independent of x) in the expansion of `(2x^2 - 5/x)^9`
Find the middle term in the expansion of `(x/y + y/x)^12`
Find the middle terms in the expansion of `(x^2 + 1/x)^7`
Find the middle term in the expansion of `(x^2 - 2/x)^8`
Find the middle term in the expansion of `(x/"a" - "a"/x)^10`
Find the middle terms in the expansion of `(x^4 - 1/x^3)^11`
In the expansion of (k + x)8, the coefficient of x5 is 10 times the coefficient of x6. Find the value of k.
Find the term containing x6 in the expansion of (2 − x) (3x + 1)9
The coefficient of x2 in the expansion of (1 + 2x)m is 112. Find m
Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board 4 Methods of Induction and Binomial Theorem Exercise 4.4 [Page 82]
State, by writing first four terms, the expansion of the following, where |x| < 1
(1 + x)−4
State, by writing first four terms, the expansion of the following, where |x| < 1
`(1 - x)^(1/3)`
State, by writing first four terms, the expansion of the following, where |x| < 1
(1 – x2)–3
State, by writing first four terms, the expansion of the following, where |x| < 1
`(1 + x)^(-1/5)`
State, by writing first four terms, the expansion of the following, where |x| < 1
(1 + x2)–1
State, by writing first four terms, the expansion of the following, where |b| < |a|
(a − b)−3
State, by writing first four terms, the expansion of the following, where |b| < |a|
(a + b)−4
State, by writing first four terms, the expansion of the following, where |b| < |a|
`("a" + "b")^(1/4)`
State, by writing first four terms, the expansion of the following, where |b| < |a|
`("a" - "b")^(-1/4)`
State, by writing first four terms, the expansion of the following, where |b| < |a|
`("a" + "b")^(-1/3)`
Simplify first three terms in the expansion of the following
(1 + 2x)–4
Simplify first three terms in the expansion of the following
`(1 + 3x)^(-1/2)`
Simplify first three terms in the expansion of the following
`(2 - 3x)^(1/3)`
Simplify first three terms in the expansion of the following
`(5 + 4x)^(-1/2)`
Simplify first three terms in the expansion of the following
`(5 - 3x)^(-1/3)`
Use binomial theorem to evaluate the following upto four places of decimal
`sqrt(99)`
Use binomial theorem to evaluate the following upto four places of decimal
`root(3)(126)`
Use binomial theorem to evaluate the following upto four places of decimal
`root(4)(16.08)`
Use binomial theorem to evaluate the following upto four places of decimal
(1.02)–5
Use binomial theorem to evaluate the following upto four places of decimal
(0.98)–3
Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board 4 Methods of Induction and Binomial Theorem Exercise 4.5 [Page 84]
Show That C0 + C1 + C2 + .... C8 = 256
Show That C0 + C1 + C2 + .... C9 = 512
Show That C1 + C2 + C3 + .... C7 = 127
Show That C1 + C2 + C3 + .... C6 = 63
Show That C0 + C2 + C4 + C6 + C8 = C1 + C3 + C5 + C7 = 128
Show That C1 + C2 + C3 + .... Cn = 2n − 1
Show That C0 + 2C1 + 3C2 + 4C3 + ... + (n + 1)Cn = (n + 2)2n−1
Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board 4 Methods of Induction and Binomial Theorem Miscellaneous Exercise 4.1 [Page 85]
Select the correct answer from the given alternatives.
The total number of terms in the expression of (x + y)100 + (x − y)100 after simplification is:
50
51
100
202
Select the correct answer from the given alternatives.
The middle term in the expansion of (1 + x)2n will be :
(n − 1)th
nth
(n + 1)th
(n + 2)th
Select the correct answer from the given alternatives.
In the expansion of (x2 − 2x)10, the coefficient of x16 is
−1680
1680
3360
6720
Select the correct answer from the given alternatives.
The term not containing x in expansion of `(1 - x)^2 (x + 1/x)^10` is
11C5
10C5
10C4
10C7
Select the correct answer from the given alternatives.
The number of terms in expansion of (4y + x)8 − (4y − x)8
4
5
8
9
Select the correct answer from the given alternatives.
The value 14C1 + 14C3 + 14C5 + ..... + 14C11 is
214 − 1
214 − 14
212
213 − 14
Select the correct answer from the given alternatives.
The value 11C2 + 11C4 + 11C6 + 11C8 is equal to
210 − 1
210 − 11
210 + 12
210 − 12
Select the correct answer from the given alternatives.
In the expansion of (3x + 2)4, the coefficient of the middle term is
36
54
81
216
Select the correct answer from the given alternatives.
The coefficient of the 8th term in the expansion of (1 + x)10 is:
7
120
10C8
210
Select the correct answer from the given alternatives.
If the coefficient of x2 and x3 in the expansion of (3 + ax)9 are the same, then the value of a is
`-7/9`
`-9/7`
`7/9`
`9/7`
Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board 4 Methods of Induction and Binomial Theorem Miscellaneous Exercise 4.2 [Pages 85 - 86]
Answer the following:
Prove, by method of induction, for all n ∈ N
8 + 17 + 26 + … + (9n – 1) = `"n"/2(9"n" + 7)`
Answer the following:
Prove, by method of induction, for all n ∈ N
12 + 42 + 72 + ... + (3n − 2)2 = `"n"/2 (6"n"^2 - 3"n" - 1)`
Answer the following:
Prove, by method of induction, for all n ∈ N
2 + 3.2 + 4.22 + ... + (n + 1)2n–1 = n.2n
Answer the following:
Prove, by method of induction, for all n ∈ N
`1/(3.4.5) + 2/(4.5.6) + 3/(5.6.7) + ... + "n"/(("n" + 2)("n" + 3)("n" + 4)) = ("n"("n" + 1))/(6("n" + 3)("n" + 4))`
Answer the following:
Given that tn+1 = 5tn − 8, t1 = 3, prove by method of induction that tn = 5n−1 + 2
Answer the following:
Prove by method of induction
`[(3, -4),(1, -1)]^"n" = [(2"n" + 1, -4"n"),("n", -2"n" + 1)], ∀ "n" ∈ "N"`
Expand (3x2 + 2y)5
Answer the following:
Expand `((2x)/3 - 3/(2x))^4`
Answer the following:
Find third term in the expansion of `(9x^2 - y^3/6)^4`
Answer the following:
Find tenth term in the expansion of `(2x^2 + 1/x)^12`
Answer the following:
Find the middle term (s) in the expansion of `((2"a")/3 - 3/(2"a"))^6`
Answer the following:
Find the middle term (s) in the expansion of `(x - 1/(2y))^10`
Answer the following:
Find the middle term (s) in the expansion of (x2+ 2y2)7
Answer the following:
Find the middle term (s) in the expansion of `((3x^2)/2 - 1/(3x))^9`
Find the coefficients of x6 in the expansion of `(3x^2 - 1/(3x))^9`.
Find the coefficients of x60 in the expansion of `(1/x^2 + x^4)^18`
Answer the following:
Find the constant term in the expansion of `((4x^2)/3 + 3/(2x))^9`
Answer the following
Find the constant term in the expansion of `(2x^2 - 1/x)^12`
Answer the following:
Prove by method of induction loga xn = n logax, x > 0, n ∈ N
Answer the following:
Prove by method of induction 152n–1 + 1 is divisible by 16, for all n ∈ N.
Answer the following:
Prove by method of induction 52n − 22n is divisible by 3, for all n ∈ N
Answer the following:
If the coefficient of x16 in the expansion of (x2 + ax)10 is 3360, find a
Answer the following:
If the middle term in the expansion of `(x + "b"/x)^6` is 160, find b
Answer the following:
If the coefficient of x2 and x3 in the expansion of (3 + kx)9 are equal, find k
Answer the following:
If the constant term in the expansion of `(x^3 + "k"/x^8)^11` is 1320, find k
Answer the following:
Show that there is no term containing x6 in the expansion of `(x^2 - 3/x)^11`
Answer the following:
Show that there is no constant term in the expansion of `(2x - x^2/4)^9`
Answer the following:
State, first four terms in the expansion of `(1 - (2x)/3)^(-1/2)`
Answer the following:
State, first four terms in the expansion of `(1 - x)^(-1/4)`
Answer the following:
State, first three terms in the expansion of `(5 + 4x) ^(-1/2)`
Answer the following:
Using binomial theorem, find the value of `root(3)(995)` upto four places of decimals
Answer the following:
Find approximate value of `1/4.08` upto four places of decimals
Answer the following:
Find the term independent of x in the in expansion of `(1 - x^2) (x + 2/x)^6`
Answer the following:
(a + bx) (1 − x)6 = 3 − 20x + cx2 + ..... then find a, b, c
Answer the following:
The 3rd term of (1 + x)n is 36x2. Find 5th term
Answer the following:
Suppose (1 + kx)n = 1 − 12x + 60x2 − .... find k and n.
Solutions for 4: Methods of Induction and Binomial Theorem
![Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 4 - Methods of Induction and Binomial Theorem Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 4 - Methods of Induction and Binomial Theorem - Shaalaa.com](/images/mathematics-and-statistics-2-arts-and-science-english-11-standard-maharashtra-state-board_6:eaa36ca82be449018bee0683dd2bba6f.jpg)
Balbharati solutions for Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 4 - Methods of Induction and Binomial Theorem
Shaalaa.com has the Maharashtra State Board Mathematics Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board Maharashtra State Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Balbharati solutions for Mathematics Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board Maharashtra State Board 4 (Methods of Induction and Binomial Theorem) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Balbharati textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.
Concepts covered in Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 4 Methods of Induction and Binomial Theorem are Principle of Mathematical Induction, Binomial Theorem for Positive Integral Index, General Term in Expansion of (a + b)n, Middle term(s) in the expansion of (a + b)n, Binomial Theorem for Negative Index Or Fraction, Binomial Coefficients.
Using Balbharati Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board solutions Methods of Induction and Binomial Theorem exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Balbharati Solutions are essential questions that can be asked in the final exam. Maximum Maharashtra State Board Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board students prefer Balbharati Textbook Solutions to score more in exams.
Get the free view of Chapter 4, Methods of Induction and Binomial Theorem Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board additional questions for Mathematics Mathematics and Statistics 2 (Arts and Science) [English] 11 Standard Maharashtra State Board Maharashtra State Board, and you can use Shaalaa.com to keep it handy for your exam preparation.