Advertisements
Advertisements
प्रश्न
Simplify first three terms in the expansion of the following
`(1 + 3x)^(-1/2)`
उत्तर
`(1 + 3x)^(-1/2) = 1 + (-1/2)(3x) + ((-1/2)(-1/2 - 1))/(2!) (3x)^2 + ...`
= `1 - (3x)/2 + (-1/2)(-3/2)(1/2)(9x^2) + ....`
= `1 - (3x)/2 + (27x^2)/8 + ...`
APPEARS IN
संबंधित प्रश्न
State, by writing first four terms, the expansion of the following, where |x| < 1
(1 + x)−4
State, by writing first four terms, the expansion of the following, where |x| < 1
`(1 - x)^(1/3)`
State, by writing first four terms, the expansion of the following, where |x| < 1
(1 – x2)–3
State, by writing first four terms, the expansion of the following, where |x| < 1
`(1 + x)^(-1/5)`
State, by writing first four terms, the expansion of the following, where |x| < 1
(1 + x2)–1
State, by writing first four terms, the expansion of the following, where |b| < |a|
`("a" + "b")^(1/4)`
State, by writing first four terms, the expansion of the following, where |b| < |a|
`("a" - "b")^(-1/4)`
State, by writing first four terms, the expansion of the following, where |b| < |a|
`("a" + "b")^(-1/3)`
Simplify first three terms in the expansion of the following
(1 + 2x)–4
Simplify first three terms in the expansion of the following
`(5 + 4x)^(-1/2)`
Simplify first three terms in the expansion of the following
`(5 - 3x)^(-1/3)`
Use binomial theorem to evaluate the following upto four places of decimal
`sqrt(99)`
Use binomial theorem to evaluate the following upto four places of decimal
`root(3)(126)`
Use binomial theorem to evaluate the following upto four places of decimal
`root(4)(16.08)`
Use binomial theorem to evaluate the following upto four places of decimal
(1.02)–5
Use binomial theorem to evaluate the following upto four places of decimal
(0.98)–3
Show That C1 + C2 + C3 + .... Cn = 2n − 1
Show That C0 + 2C1 + 3C2 + 4C3 + ... + (n + 1)Cn = (n + 2)2n−1
