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प्रश्न
Answer the following:
State, first four terms in the expansion of `(1 - x)^(-1/4)`
उत्तर
`(1 - x)^(-1/4) = 1- (-1/4)x + ((-1/4)(-1/4 - 1))/(2!) x^2 - ((-1/4)(-1/4 - 1)(-1/4 - 2))/(3!) x^3 + ...`
= `1 + x/4 + (-1/4)(-5/4)(1/2)x^2 - (-1/4)(-5/4)(-9/4)(1/6)x^3 + ...`
= `1 + x/4 + (5x^2)/32 + (15x^3)/128 + ...`
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