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प्रश्न
In the following expansion, find the indicated term.
`((4x)/5 - 5/(2x))^9`, 7th term
उत्तर
We know that the (r + 1)th term in the expansion of (a + b)n is
tr+1 = nCr an–r br
Hence a = `(4x)/5` b = `-5/(2x)`, n = 9 and for t7, r = 6
∴ 7th term in the expansion of `((4x)/5 - 5/(2x))^9`
= t7 = `""^9"C"_6((4x)/5)^(9 - 6) ((-5)/(2x))^6`
= `(9!)/(6! 3!) xx ((4x)/5)^3 xx ((-5)/(2x))^6`
...[∵ nCr = nCn–r]
= `(9 xx 8 xx 7)/(3 xx 2 xx 1) xx (4^3.x^3)/5^3 xx 5^6/(2^6.x^6)`
= `(9 xx 8 xx 7)/(3 xx 2 xx 1) xx (64.x^3)/125 xx 15625/(64.x^6)`
= `504/6 xx 125/(x^3)`
= `84 xx 125/(x^3)`
= `10500/x^3`
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