Advertisements
Advertisements
प्रश्न
Sides of two similar triangles are in the ratio 4 : 9. Areas of these triangles are in the ratio
पर्याय
2 : 3
4 : 9
81 : 16
16 : 81
उत्तर
If two triangles are similar to each other, then the ratio of the areas of these triangles will be equal to the square of the ratio of the corresponding sides of these triangles.
It is given that the sides are in the ratio 4:9.
Therefore, ratio between areas of these triangles = `(4/9)^2 = 16/81`
Hence, the correct answer is 16 : 81.
APPEARS IN
संबंधित प्रश्न
D, E, F are the mid-point of the sides BC, CA and AB respectively of a ∆ABC. Determine the ratio of the areas of ∆DEF and ∆ABC.
D and E are points on the sides AB and AC respectively of a ∆ABC such that DE || BC and divides ∆ABC into two parts, equal in area. Find
Diagonals of a trapezium ABCD with AB || DC intersect each other at the point O. If AB = 2 CD, find the ratio of the areas of triangles AOB and COD.
Triangles ABC and DEF are similar If AB = 1.2 cm and DE = 1.4 cm, find the ratio of the areas of ΔABC and ΔDEF.
ABCD is a trapezium in which AB || CD. The diagonals AC and BD intersect at O. Prove that: (i) ΔAOB and ΔCOD (ii) If OA = 6 cm, OC = 8 cm,
Find:(a) `("area"(triangleAOB))/("area"(triangleCOD))`
(b) `("area"(triangleAOD))/("area"(triangleCOD))`
If ΔABC and ΔBDE are equilateral triangles, where D is the mid-point of BC, find the ratio of areas of ΔABC and ΔBDE.
If ∆XYZ ~ ∆PQR and A(∆XYZ) = 25 cm2, A(∆PQR) = 4 cm2 then XY : PQ = ?
ΔABC ~ ΔPQR. In ΔABC, AB = 5.4 cm, BC = 4.2 cm, AC = 6.0 cm, AB:PQ = 3:2, then construct ΔABC and ΔPQR.
In the adjoining figure, ΔADB ∼ ΔBDC. Prove that BD2 = AD × DC.
Use area theorem of similar triangles to prove congruency of two similar triangles with equal areas.
