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प्रश्न
Simplify:
\[\left( 4^{- 1} \times 3^{- 1} \right)^2\]
बेरीज
उत्तर
`(4^(-1)xx3^(-1))^2-(1/4xx1/3)^2` `->(a^(-1)=1/a)`
`=(1/12)^2`
`=1^2/12^2` `->(a/b)^n=(a^n)/(b^n)`
`=1/24`
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