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सी.आई.एस.सी.ई.आयसीएसई ICSE Class 7

Simplify, Giving Solution with Positive Index (5a2b) (2ab2) (A3b) - Mathematics

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प्रश्न

Simplify, giving Solution with positive index

(5a2b) (2ab2) (a3b) 

बेरीज

उत्तर

(5a2b) (2ab2) (a3b) 

= 5 . 2 . a2+1+3 b1+2+1 = 10a6b4 

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Laws of Exponents (Through Observing Patterns to Arrive at Generalisation.)
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Exponents (Including Laws of Exponents) - Exercise 5 (B)

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सेलिना Concise Mathematics [English] Class 7 ICSE
पाठ 5 Exponents (Including Laws of Exponents)
Exercise 5 (B) | Q 3.07
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