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प्रश्न
Solve `(2x)/(x - 3) + 1/(2x + 3) + (3x + 9)/((x - 3)(2x +3)) = 0; x != 3, x != - 3/2`
उत्तर
`(2x)/(x - 3) + 1/(2x + 3) + (3x + 9)/((x - 3)(2x +3)) = 0; x != 3, x != - 3/2`
`=> (2x(2x + 3) + 1(x - 3) + 3x + 9)/((x - 3)(2x + 3)) = 0`
`=> 4x^2 + 6x + x - 3 + 3x + 9 = 0`
`=> 4x^2 + 10x + 6 = 0`
`=> 4x(x + 1) + 6(x + 1) = 0`
`= (x + 1)(4x + 6) = 0`
`=> x + 1 = 0 or 4x + 6 = 0`
`=> x = -1 or x = (-6)/4 = (-3)/2` (reject)
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