Advertisements
Advertisements
प्रश्न
`9x-3x-2=0`
उत्तर
We write, `-3x=3x-6x as 9x^2xx(-2)=-18x^2=3x xx(-6x)`
∴ `9x^2-3x-2=0`
⇒`9x^2+3x-6x-2=0`
⇒`3x(3x+1)-2(3x+1)=0`
⇒` (3x+1)(3x-2)=0`
⇒`3x+1=0 or 3x-2=0`
⇒ `x=-1/3 or x=2/3`
Hence, the roots of the given equation are `-1/3 and 2/3`
APPEARS IN
संबंधित प्रश्न
Solve the quadratic equation x2 – 3(x + 3) = 0; Give your answer correct to two significant figures.
In the following, find the value of k for which the given value is a solution of the given equation:
7x2 + kx - 3 = 0, `x=2/3`
Solve `x/3 + 3/(6 - x) = (2(6 + x))/15; (x ≠ 6)`
Solve `(1200/x + 2)(x - 10) - 1200 = 60`
`3sqrt(x/5)+3sqrt(5/x)=10`
Which of the following are quadratic equation in x?
`1/3x^2+1/5x-2=0`
`6x^2+x--12=0`
`x^2-(1+sqrt2)x+sqrt2=0`
Find which of the following equations are quadratic:
5x2 – 8x = –3(7 – 2x)
Find the solution of the equation 2x2 – mx – 25n = 0; if m + 5 = 0 and n – 1 = 0.
