Advertisements
Advertisements
प्रश्न
`9x-3x-2=0`
उत्तर
We write, `-3x=3x-6x as 9x^2xx(-2)=-18x^2=3x xx(-6x)`
∴ `9x^2-3x-2=0`
⇒`9x^2+3x-6x-2=0`
⇒`3x(3x+1)-2(3x+1)=0`
⇒` (3x+1)(3x-2)=0`
⇒`3x+1=0 or 3x-2=0`
⇒ `x=-1/3 or x=2/3`
Hence, the roots of the given equation are `-1/3 and 2/3`
APPEARS IN
संबंधित प्रश्न
Represent the following situation in the form of a quadratic equation:
The area of a rectangular plot is 528 m2. The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.
Solve : x(x – 5) = 24
Solve : (2x – 3)² = 49
Solve the following equation using the formula:
`(2x)/(x - 4) + (2x - 5)/(x - 3) = 8 1/3`
`x^2+2sqrt2x-6=0`
If one root of the quadratic equation 6x2 – x – k = 0 is
Show that one root of the quadratic equation x2 + (3 – 2a)x – 6a = 0 is –3. Hence, find its other root.
Solve the following equation by using formula :
`(x + 1)/(x + 3) = (3x + 2)/(2x + 3)`
Solve the following equation by using quadratic equations for x and give your 5x(x + 2) = 3
If x2 – 3x + 2 = 0, values of x correct to one decimal place are ______.
