मराठी
सी.आई.एस.सी.ई.आयसीएसई ICSE Class 8

Solve: ("6x" + 1)/2 + 1 = ("7x" - 3)/3 - Mathematics

Advertisements
Advertisements

प्रश्न

Solve: `("6x" + 1)/2 + 1 = ("7x" - 3)/3`

बेरीज

उत्तर

`("6x" + 1)/2 + 1 = ("7x" - 3)/3`


`=> ((6"x" + 1) + 1 xx 2)/2 = ("7x" - 3)/3`


`=> ("6x" + 1 + 2)/2 = ("7x" - 3)/3`


`=> ("6x" + 3)/2 = ("7x" - 3)/3`

⇒ 3(6x + 3) = 2(7x - 3)

⇒ 18x + 9 = 14x - 6

⇒ 18x - 14x = - 6 - 9

⇒ 4x = -15

∴ x = `(-15)/4`

shaalaa.com
Solving Linear Inequations
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 14: Linear Equations in one Variable - Exercise 14 (C) [पृष्ठ १७०]

APPEARS IN

सेलिना Concise Mathematics [English] Class 8 ICSE
पाठ 14 Linear Equations in one Variable
Exercise 14 (C) | Q 1.14 | पृष्ठ १७०
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×