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Chapters
2: Exponents
3: Squares and Square Root
4: Cubes and Cube Roots
5: Playing with Numbers
6: Sets
7: Percent and Percentage
8: Profit, Loss and Discount
9: Interest
10: Direct and Inverse Variations
11: Algebraic Expressions
12: Identities
13: Factorisation
▶ 14: Linear Equations in one Variable
15: Linear Inequations
16: Understanding Shapes
17: Special Types of Quadrilaterals
18: Constructions
19: Representing 3-D in 2-D
20: Area of a Trapezium and a Polygon
21: Surface Area, Volume and Capacity
22: Data Handling
23: Probability
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Solutions for Chapter 14: Linear Equations in one Variable
Below listed, you can find solutions for Chapter 14 of CISCE Selina for Concise Mathematics [English] Class 8 ICSE.
Selina solutions for Concise Mathematics [English] Class 8 ICSE 14 Linear Equations in one Variable Exercise 14 (A) [Pages 165 - 166]
Solve the following equation:
20 = 6 + 2x
Solve the following equation:
15 + x = 5x + 3
Solve the following equation:
`(3"x" + 2)/("x" - 6) = -7`
Solve the following equation:
3a - 4 = 2(4 - a)
Solve the following equation:
3(b - 4) = 2(4 - b)
Solve the following equation:
`("x"+2)/9 = ("x" + 4)/11`
Solve the following equation:
`("x"- 8)/5 = ("x" - 12)/9`
Solve the following equation:
5(8x + 3) = 9(4x + 7)
Solve the following equation:
3(x + 1) = 12 + 4(x - 1)
Solve the following equation:
`"3x"/4 - 1/4("x" - 20) = "x"/4 + 32`
Solve the following equation:
`3"a" - 1/5 = "a"/5 + 5 2/5`
Solve the following equation:
`"x"/3 - 2 1/2 = "4x"/9 - "2x"/3`
Solve the following equation:
`(4(y + 2))/5 = 7 + "5y"/13`
Solve the following equation:
`("a" + 5)/6 - ("a" + 1)/9 = ("a" + 3)/4`
Solve the following equation:
`("2x" - 13)/5 - ("x" - 3)/11 = ("x" - 9)/5 + 1`
Solve the following equation:
6(6x - 5) - 5(7x - 8) = 12(4 - x) + 1
Solve the following equation:
(x - 5)(x + 3) = (x - 7)(x + 4)
Solve the following equation:
(x – 5)2 – (x + 2)2 = -2
Solve the following equation:
(x - 1 )(x + 6) - (x - 2)(x - 3) = 3
Solve the following equation:
`(3"x")/("x" + 6) - "x"/("x" + 5) = 2`
Solve the following equation:
`1/("x - 1") + 2/("x" - 2) = 3/("x" - 3)`
Solve the following equation:
`("x" - 1)/("7x" - 14) = ("x" - 3)/("7x" - 26)`
Solve the following equation:
`1/("x" - 1) - 1/"x" = 1/("x" + 3) - 1/("x" + 4)`
Solve: `"2x"/3 - ("x" - 1)/6 + ("7x" - 1)/4 = 2 1/6` Hence, find the value of 'a', if `1/"a" + 5"x" = 8`
Solve: `(4-3"x")/5 + (7 - "x")/3 + 4 1/3 = 0` Hence, find the value of 'p', if 3p - 2x + 1 = 0
Solve: 0.25 + `1.95/"x" = 0.9`
Solve:
`5x − (4x + (5x - 4)/7) = (4x - 14)/3`
Selina solutions for Concise Mathematics [English] Class 8 ICSE 14 Linear Equations in one Variable Exercise 14 (B) [Page 169]
Fifteen less than 4 times a number is 9. Find the number.
If Megha’s age is increased by three times her age, the result is 60 years. Find her age
28 is 12 less than 4 times a number. Find the number.
Five less than 3 times a number is -20. Find the number.
Fifteen more than 3 times Neetu’s age is the same as 4 times her age. How old is she ?
A number decreased by 30 is the same as 14 decreased by 3 times the number; Find the number.
A’s salary is same as 4 times B’s salary. If together they earn Rs.3,750 a month, find the salary of each.
Separate 178 into two parts so that the first part is 8 less than twice the second part.
Six more than one-fourth of a number is two-fifth of the number. Find the number.
The length of a rectangle is twice its width. If its perimeter is 54 cm; find its length.
A rectangle’s length is 5 cm less than twice its width. If the length is decreased by 5 cm and width is increased by 2 cm; the perimeter of the resulting rectangle will be 74 cm. Find the length and width of the origi¬nal rectangle.
The sum of three consecutive odd numbers is 57. Find the numbers.
A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.
A man is 42 years old and his son is 12 years old. In how many years will the age of the son be half the age of the man at that time?
A man completed a trip of 136 km in 8 hours. Some part of the trip was covered at 15 km/hr and the remaining at 18 km/hr. Find the part of the trip covered at 18 km/hr.
The difference of two numbers is 3 and the difference of their squares is 69. Find the numbers.
Two consecutive natural numbers are such that one-fourth of the smaller exceeds one-fifth of the greater by 1. Find the numbers.
Three consecutive whole numbers are such that if they be divided by 5, 3 and 4 respectively; the sum of the quotients is 40. Find the numbers.
If the same number be added to the numbers 5, 11, 15 and 31, the resulting numbers are in proportion. Find the number.
The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7 : 4. Find their present ages
Selina solutions for Concise Mathematics [English] Class 8 ICSE 14 Linear Equations in one Variable Exercise 14 (C) [Pages 169 - 170]
Solve: `1/3"x" - 6 = 5/2`
Solve: `(2"x")/3 - (3"x")/8 = 7/12`
Solve the following equation and also verify your solution:
(x + 2)(x + 3) + (x − 3)(x − 2) − 2x(x + 1) = 0
Solve:
`1/10 - 7/x = 35`
Solve:
13(x − 4) - 3(x − 9) − 5(x + 4) = 0
Solve: `"x" + 7 - "8x"/3 = "17x"/6 - "5x"/8`
Solve: `(3"x" - 2)/4 - ("2x" + 3)/3 = 2/3 - "x"`
Solve:
`(x + 2)/6 - ((11 - x)/3 - 1/4) = (3x - 4)/12`
Solve: `2/"5x" - 5/"3x" = 1/15`
Solve: `("x" + 2)/3 - ("x" + 1)/5 = ("x" - 3)/4 - 1`
Solve: `(3"x" - 2)/3 + (2"x" + 3)/2 = "x" + 7/6`
Solve: `"x" - ("x" - 1)/2 = 1 - ("x" - 2)/3`
Solve: `("9x" + 7)/2 - ("x" - ("x" - 2)/7) = 36`
Solve: `("6x" + 1)/2 + 1 = ("7x" - 3)/3`
After 12 years, I shall be 3 times as old as 1 was 4 years ago. Find my present age.
A man sold an article for ₹ 396 and gained 10% on it. Find the cost price of the article
The sum of two numbers is 4500. If 10% of one number is 12.5% of the other, find the numbers.
The sum of two numbers is 405 and their ratio is 8 : 7. Find the numbers.
The ages of A and B are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.
Find a number whose double is 45 greater than its half.
The difference between the squares of two consecutive numbers is 31. Find the numbers.
Find a number such that when 5 is subtracted from 5 times the number, the result is 4 more than twice the number.
The numerator of a fraction is 5 less than its denominator. If 3 is added to the numerator, and denominator both, the fraction becomes`4/5`. Find the original fraction.
Solutions for 14: Linear Equations in one Variable
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Selina solutions for Concise Mathematics [English] Class 8 ICSE chapter 14 - Linear Equations in one Variable
Shaalaa.com has the CISCE Mathematics Concise Mathematics [English] Class 8 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Selina solutions for Mathematics Concise Mathematics [English] Class 8 ICSE CISCE 14 (Linear Equations in one Variable) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Concise Mathematics [English] Class 8 ICSE chapter 14 Linear Equations in one Variable are Simple Linear Equations in One Variable, Solving Linear Inequations, Equations Reducible to the Linear Form, Linear Equation in One Variable.
Using Selina Concise Mathematics [English] Class 8 ICSE solutions Linear Equations in one Variable exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Selina Solutions are essential questions that can be asked in the final exam. Maximum CISCE Concise Mathematics [English] Class 8 ICSE students prefer Selina Textbook Solutions to score more in exams.
Get the free view of Chapter 14, Linear Equations in one Variable Concise Mathematics [English] Class 8 ICSE additional questions for Mathematics Concise Mathematics [English] Class 8 ICSE CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.