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सी.आई.एस.सी.ई.आयसीएसई ICSE Class 8

Solve: x+26-(11-x3-14)=3x-412 - Mathematics

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प्रश्न

Solve:

`(x + 2)/6 - ((11 - x)/3 - 1/4) = (3x - 4)/12`

बेरीज

उत्तर

`"x" + 2/6 - 11 - "x"/3 - 1/4 = 3"x" - 4/12`

`=> ("x" + 2)/6 - (4(11 - x) - 1 xx 3)/12 = (3"x" - 4)/12`

`=> ("x" + 2)/6 - (44 + 4x + 3)/12 = (3"x" - 4)/12`

`=> (2("x" + 2) - 41 + 4"x")/12 = (3"x" - 4)/12`

`=> (2"x" + 4 - 41 + 4"x")/12 = (3"x" - 4)/12`

`=> (6"x" - 37)/12 = (3"x" - 4)/12`

⇒ 12(6x − 37) = 12(3x − 4)

⇒ 72x − 444 = 36x − 48

⇒ 72x − 36x = −48 + 444

⇒ 36x = 396

⇒ x = `396/36 = 11`

∴ x = 11

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Solving Linear Inequations
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पाठ 14: Linear Equations in one Variable - Exercise 14 (C) [पृष्ठ १६९]

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सेलिना Concise Mathematics [English] Class 8 ICSE
पाठ 14 Linear Equations in one Variable
Exercise 14 (C) | Q 1.08 | पृष्ठ १६९
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