Advertisements
Advertisements
प्रश्न
Solve : 7 > 3x - 8 ; x ∈ N.
उत्तर
7 > 3x – 8
⇒ 7 – 3x > 3x – 3x – 8 (Subtracting 3x)
⇒ 7 – 7 – 3x > 3x – 3x – 8 – 7 (Subtracting 7)
⇒ -3x > -15
⇒ x < 5 (Dividing by -3)
Required Answer = {1, 2, 3, 4}
Note : Division by negative number reverses the inequality.
APPEARS IN
संबंधित प्रश्न
If the replacement set is the set of natural numbers, solve: x - 5 < 0
If the replacement set is the set of natural numbers, solve: x + 1 ≤ 7
If the replacement set is the set of natural numbers, solve: 4x + 1 ≥ 17
If the replacement set = {- 6,. - 3, 0, 3, 6, 9}; find the truth set of the following : 2x - 1 > 9
If the replacement set = {- 6,. - 3, 0, 3, 6, 9}; find the truth set of the following : 3x + 7 < 1
Solve : - 17 < 9y - 8; y ∈ Z.
Solve: `-5 ("x" + 4) > 30 ; "x" ∈ "Z"`
Solve the inequation 18 – 3 (2x – 5) > 12; x ∈ W.
Solve the inequation `("2x" + 1)/3 + 15 ≤ 17;` x ∈ W.
Solve: 15 – 2(2x – 1) < 15, x ∈ Z.