Advertisements
Advertisements
प्रश्न
Solve and graph the solution set of:
x + 5 ≥ 4(x – 1) and 3 – 2x < –7, x ∈ R
उत्तर
x + 5 ≥ 4(x – 1) and 3 – 2x < –7
9 ≥ 3x and – 2x < – 10
3 ≥ x and x > 5
∴ Solution set = Empty set
APPEARS IN
संबंधित प्रश्न
`2x <= -7 => (2x)/(-4) >= (-7)/(-4)`
If a – c > b – d; then a + d > b + c
For graph given alongside, write an inequation taking x as the variable:
Represent the solution of the following inequalities on the real number line:
2 – 3x > 7 – 5x
If 5x – 3 ≤ 5 + 3x ≤ 4x + 2, express it as a ≤ x ≤ b and then state the values of a and b.
Solve for x in the following in-equation, if the replacement set is R;
3x + 25 < 8x - 10
Solve for x : `("x" + 3)/3 <= ("x" + 8)/4` , where x is a positive even number.
Solve the given inequation and graph the solution on the number line
2y - 3
Solve the following inequalities in the given universal set:
4x + 2 ≤ 2x - 7; x ∈ I
The value of x for the inequation 3x + 15 < 5x + 13, x ∈ Z is ______.
