Advertisements
Advertisements
प्रश्न
Solve the following inequalities in the given universal set:
4x + 2 ≤ 2x - 7; x ∈ I
उत्तर
We have
4x + 2 ≤ 2x - 7; x ∈ I
⇒ 4x - 2x ≤ -7 -2
⇒ 2x ≤ -9
⇒ x ≤ -9/2
As x ∈ I, x can take values -5, -6, -7, ......,
so x = {-5, -6, -7, -8, .......,}
This set can be drawn on number line as x ≤ -9/2.
APPEARS IN
संबंधित प्रश्न
`-5x >= 15 => x >= -3`
If a > b, then a + c > b + c
If a < b, and c > 0, then a – c > b – c where a, b, c and d are real numbers and c ≠ 0.
Represent the following in-equalities on real number line :
−5 < × ≤ −1
Solve for x in the following in equation, if the replacement set is N<10:
x + 5 > 11
Solve for x in the following in-equation, if the replacement set is R;
7x + 11 > 16 - 3x
For each inequality, determine which of the given numbers are in the solution set:
2x + 3 >11; -3, 4, 5, 7
Solve the following inequalities in the given universal set:
5x - 3 < 6x - 2; x ∈ N
Find the solution set of the following inequalities and draw the graph of their solutions sets:
| x - 1 | > 3
Find the solution set of the following inequalities and draw the graph of their solutions sets:
`|(x - 5)/(3)| < 6`
