Advertisements
Advertisements
प्रश्न
Solve the following inequalities in the given universal set:
4x + 2 ≤ 2x - 7; x ∈ I
उत्तर
We have
4x + 2 ≤ 2x - 7; x ∈ I
⇒ 4x - 2x ≤ -7 -2
⇒ 2x ≤ -9
⇒ x ≤ -9/2
As x ∈ I, x can take values -5, -6, -7, ......,
so x = {-5, -6, -7, -8, .......,}
This set can be drawn on number line as x ≤ -9/2.
APPEARS IN
संबंधित प्रश्न
If x ∈ N, find the solution set of inequations.
5x + 3 ≤ 2x + 18
If the replacement set is the set of whole numbers, solve:
18 ≤ 3x – 2
If the replacement set is the set of real numbers, solve:
– 4x ≥ – 16
For graph given alongside, write an inequation taking x as the variable:
Represent the solution of the following inequalities on the real number line:
1 + x ≥ 5x – 11
If 5x – 3 ≤ 5 + 3x ≤ 4x + 2, express it as a ≤ x ≤ b and then state the values of a and b.
Solve for x in the following in-equation, if the replacement set is R;
3x + 2 ≤ 11
Solve for x in the following in-equation, if the replacement set is R;
3x + 25 < 8x - 10
Solve for x : 7 + 5x > x - 13, where x is a negative integer.
Solve the following inequation and represent the solution set on the number line:
`4x - 19 < (3x)/(5) -2 ≤ (-2)/(5)+ x , x ∈ "R"`
