Advertisements
Advertisements
Question
Solve the following inequalities in the given universal set:
4x + 2 ≤ 2x - 7; x ∈ I
Solution
We have
4x + 2 ≤ 2x - 7; x ∈ I
⇒ 4x - 2x ≤ -7 -2
⇒ 2x ≤ -9
⇒ x ≤ -9/2
As x ∈ I, x can take values -5, -6, -7, ......,
so x = {-5, -6, -7, -8, .......,}
This set can be drawn on number line as x ≤ -9/2.
APPEARS IN
RELATED QUESTIONS
If a – c > b – d; then a + d > b + c
If the replacement set is the set of whole numbers, solve:
3x – 1 > 8
Find the largest value of x for which 2(x – 1) ≤ 9 – x and x ∈ W.
Solve for x in the following in-equation, if the replacement set is R;
3x + 25 < 8x - 10
Solve for x in the following in-equation, if the replacement set is R;
x + 7 ≥ 15 + 3x
Solve for x in the following in-equation, if the replacement set is R;
2x - 7 ≥ 5x + 8
Solve for x : 6 - 10x < 36, x ∈ {-3, -2, -1, O, 1, 2}
Find the solution set of the following inequalities and draw the graph of their solutions sets:
`|(x - 5)/(3)| < 6`
Solve the following inequalities and graph their solution set:
`(2x - 5)/(x + 2) < 2`
The solution set for the inequation – 2x + 7 ≤ 3, x ∈ R is ______.