Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation for x :
9x2 − 6b2x − (a4 − b4) = 0
उत्तर
For the given quadratic equation 9x2−6b2x−(a4−b4)=0, discriminant is calculated by
D=(−6b2)2−4×9×[−(a4−b4)]
= 36b4+36(a4−b4)
=36a4
Using the quadratic formula, we get
`x=(6b^2+-sqrt(36a^4))/(2xx9)`
`= (6b^2+-6a^2)/18`
`=(b^2+-a^2)/3`
`:. x=(b^2+a^2)/3" or "(b^2-a^2)/3`
APPEARS IN
संबंधित प्रश्न
Determine the nature of the roots of the following quadratic equation:
9a2b2x2 - 24abcdx + 16c2d2 = 0
Find the values of k for which the roots are real and equal in each of the following equation:
(3k+1)x2 + 2(k + 1)x + k = 0
Find the values of k for which the roots are real and equal in each of the following equation:
x2 - 2(k + 1)x + (k + 4) = 0
Find the value of the discriminant in the following quadratic equation:
2x2 - 5x + 3 = 0
If a = 1, b = 8 and c = 15, then find the value of `"b"^2 - 4"ac"`
If a = 1, b = 4, c = – 5, then find the value of b2 – 4ac
α and β are the roots of 4x2 + 3x + 7 = 0, then the value of `1/α + 1/β` is:
The roots of the equation (b – c) x2 + (c – a) x + (a – b) = 0 are equal, then:
Find the nature of the roots of the quadratic equation:
4x2 – 5x – 1 = 0
Solve for x: `5/2 x^2 + 2/5 = 1 - 2x`.
