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प्रश्न
Solve the following quadratic equations by factorization:
a2b2x2 + b2x - a2x - 1 = 0
उत्तर
We have been given
a2b2x2 + b2x - a2x - 1 = 0
b2x(a2x + 1) - 1(a2x + 1) = 0
(b2x - 1)(a2x + 1) = 0
Therefore,
b2x - 1 = 0
b2x = 1
`x=1/b^2`
or,
a2x + 1 = 0
a2x = -1
`x=-1/a^2`
Hence, `x=1/b^2` or `x=-1/a^2`
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