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प्रश्न
Solve the following quadratic equations by factorization:
`x^2+(a+1/a)x+1=0`
उत्तर
We have been given
`x^2+(a+1/a)x+1=0`
`x^2+ax+1/ax+1=0`
`x(x+a)+1/a(x+a)=0`
`(x+1/a)(x+a)=0`
Therefore,
`x+1/a=0`
`x=-1/a`
or,
x + a = 0
x = -a
Hence, `x=-1/a` or x = -a
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