Advertisements
Advertisements
प्रश्न
Solve the following quadratic equations by factorization:
x2 - x - a(a + 1) = 0
उत्तर
We have been given
x2 - x - a(a + 1) = 0
x2 + ax - (a + 1)x - a(a + 1) = 0
x(x + a) - (a + 1)(x + a) = 0
(x - (a + 1))(x + a) = 0
Therefore,
x - (a + 1) = 0
x = (a + 1)
or,
x + a = 0
x = -a
Hence, x = a + 1 or x = -a
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation by Factorisation method: x2 + 7x + 10 = 0
The sum of ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man's age at the time. Find their present ages.
Solve 2x2 – 9x + 10 =0; when x ∈ Q
The sum of the squares of two consecutive positive integers is 365. Find the integers.
If the sum of the roots of the equation \[x^2 - \left( k + 6 \right)x + 2\left( 2k - 1 \right) = 0\] is equal to half of their product, then k =
Solve the following equation:
`("x" + 1)/("x" - 1) - ("x" - 1)/("x" + 1) = 5/6 , "x" ≠ -1,1`
Solve the equation 2x `-(1)/x` = 7. Write your answer correct to two decimal places.
If the product of two consecutive even integers is 224, find the integers.
Five times a certain whole number is equal to three less than twice the square of the number. Find the number.
The hypotenuse of a right-angled triangle is 1 m less than twice the shortest side. If the third side is 1 m more than the shortest side, find the sides of the triangle.