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प्रश्न
Solve the equation: 3x2 – 8x – 1 = 0 for x.
उत्तर
Given quadratic equation is: 3x2 – 8x – 1 = 0
On comparing the above equation with ax2 + bx + c = 0, we get
a = 3, b = –8 and c = –1
Solution of x is x = `(-b +- sqrt(b^2 - 4ac))/(2a)`
= `(-(-8) +- sqrt((-8)^2 - 4(3)(-1)))/(2 xx 3)`
= `(8 +- 2sqrt(19))/6`
= `(4 +- sqrt(19))/3`
∴ x = `(4 + sqrt(19))/3` and x = `(4 - sqrt(19))/3`
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