Question

Solve the following equation: ${\displaystyle \text{2z}-2\frac{1}{2}=3\frac{1}{3}}$

Answer 1

${\displaystyle \text{2z}-2\frac{1}{2}=3\frac{1}{3}}$

⇒${\displaystyle \text{2z}-2\frac{1}{2}+2\frac{1}{2}=3\frac{1}{3}+2\frac{1}{2}}$  ..(Adding ${\displaystyle 2\frac{1}{2}}$ to both sides) 

⇒ 2z = ${\displaystyle \frac{10}{3}+\frac{5}{2}}$ 

⇒ ${\displaystyle \frac{20+15}{6}=\frac{35}{6}}$

⇒ ${\displaystyle \frac{\text{2z}}{2}=\frac{35}{6\times 2}}$      ....(Dividing by 2)

⇒ z = ${\displaystyle \frac{35}{12}=2\frac{11}{12}}$