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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता ८ वी

Solve the following equation. 3(y + 8) = 10(y − 4) + 8 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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प्रश्न

Solve the following equation.

3(y + 8) = 10(y − 4) + 8

बेरीज

उत्तर

3(y + 8) = 10(y − 4) + 8

⇒ 3y + 24 = 10y - 40 + 8

⇒ 3y + 24 = 10y - 32

Adding 32 to both sides

⇒ 3y + 24 + 32 = 10y - 32 + 32

⇒ 3y + 56 = 10y

Subtracting 3y from both sides

⇒ 3y + 56 - 3y = 10y - 3y

⇒ 56 = 7y

Dividng both sides by 7 

⇒ `(7"y")/7 = 56/7`

⇒ y = 8

Hence, y = 8 is the solution of the equation.

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Solution of Equations in One Variable
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 12: Equations in one variable - Practice Set 12.1 [पृष्ठ ७७]

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बालभारती Mathematics [English] 8 Standard Maharashtra State Board
पाठ 12 Equations in one variable
Practice Set 12.1 | Q 2.08 | पृष्ठ ७७
बालभारती Integrated 8 Standard Part 3 [English Medium] Maharashtra State Board
पाठ 3.3 Equations in One Variable
Practice Set 12.1 | Q 2. (8) | पृष्ठ ५२
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