मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता ८ वी

The equation given below is followed by the value of the variable. Decide whether this value is the solution to that equation. 3 − y = 4, y = −1, 1, 2 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

Advertisements
Advertisements

प्रश्न

The equation given below is followed by the value of the variable. Decide whether this value is the solution to that equation.

 3 − y = 4, y = −1, 1, 2

बेरीज

उत्तर

3 – y = 4 …(i)

Substituting y = −1 in L.H.S. of equation (i),

L.H.S. = 3 – (−1)

= 3 + 1

= 4

R.H.S. = 4

∴ L.H.S. = R.H.S.

∴ y = −1 is the solution of the given equation.

Substituting y = 1 in L.H.S. of equation (i),

L.H.S. = 3 − (1)

= 2

R.H.S. = 4

∴ L.H.S. ≠ R.H.S.

∴ y = 1 is not the solution of the given equation.

Substituting y = 2 in L.H.S. of equation (i),

L.H.S. = 3 − (2)

= 1

R.H.S. = 4

∴ L.H.S. ≠ R.H.S.

∴ y = 2 is not the solution of the given equation.

shaalaa.com
Solution of Equations in One Variable
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 12: Equations in one variable - Practice Set 12.1 [पृष्ठ ७७]

APPEARS IN

बालभारती Mathematics [English] 8 Standard Maharashtra State Board
पाठ 12 Equations in one variable
Practice Set 12.1 | Q 1.4 | पृष्ठ ७७
बालभारती Integrated 8 Standard Part 3 [English Medium] Maharashtra State Board
पाठ 3.3 Equations in One Variable
Practice Set 12.1 | Q 1. (4) | पृष्ठ ५२
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×