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Question
The equation given below is followed by the value of the variable. Decide whether this value is the solution to that equation.
3 − y = 4, y = −1, 1, 2
Solution
3 – y = 4 …(i)
Substituting y = −1 in L.H.S. of equation (i),
L.H.S. = 3 – (−1)
= 3 + 1
= 4
R.H.S. = 4
∴ L.H.S. = R.H.S.
∴ y = −1 is the solution of the given equation.
Substituting y = 1 in L.H.S. of equation (i),
L.H.S. = 3 − (1)
= 2
R.H.S. = 4
∴ L.H.S. ≠ R.H.S.
∴ y = 1 is not the solution of the given equation.
Substituting y = 2 in L.H.S. of equation (i),
L.H.S. = 3 − (2)
= 1
R.H.S. = 4
∴ L.H.S. ≠ R.H.S.
∴ y = 2 is not the solution of the given equation.
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